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The following piece of code uses __interrupt keyword to define an ISR. Comment on the correctness of the code.

The following piece of code uses __interrupt keyword to define an ISR. Comment on the correctness of the code.

题目类型: 技术面试题

这是一道技术面试题,常见于澳洲IT公司面试中。

难度: hard

标签: interviewbit, embedded-c, topic-specific, embedded, c

参考答案摘要

__interrupt double calculate_circle_area (double radius){ double circle_area = PI ∗ radius ∗ radius; printf ( 'Area = %f ' , circle_area); return circle_area; } Following things are wrong with the giv...

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The following piece of code uses __interrupt keyword to define an ISR. Comment on the correctness of the code.

Hardembeddedc

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