There are 9 coins and a weighing balance. 8 coins are of the same weight and 1 coin is heavier. In how many minimum numbers of iterations can you find out the heaviest coin in the worst case?
There are 9 coins and a weighing balance. 8 coins are of the same weight and 1 coin is heavier. In how many minimum numbers of iterations can you find out the heaviest coin in the worst case?
题目类型: 技术面试题
这是一道技术面试题,常见于澳洲IT公司面试中。
难度: easy
标签: interviewbit, pwc, company-specific
目标公司: PricewaterhouseCoopers
参考答案摘要
Most people try to divide the coins into 2 groups. But the trick here is to divide them into 3 groups. The reason being if we divide coins into 2 groups and weigh them, we can only discard one group. ...
答题技巧
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